The slope of the tangent to the curve y = x2 –x at the point, where the line y = 2 cuts the curve in the Ist quadrant, is

EXERCISE 8 A Q. 21
Q.21) The slope of the tangent to the curve y = x² –x at the point, where the line y = 2 cuts the curve in the Ist quadrant, is

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Correct

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y = x2 –x ---(1)
y = 2 -----(2)
comparing (1) and (2) , we get
∴ x² - x - 2 = 0
∴ (x - 2 )(x + 1 ) = 0
∴ x = 2 and x = -1
It is in I quardent , so x = 2.
y = x²> - x
Diff.w.r.t. x, we get
dy/dx = 2x - 1
dy/dx at x = 2 = 2(2) - 1 = 3.
Answer : (b)

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